SOLUTION: The problem states - Given J (-3,4) and K (-7, -2), find the magnitude of JK to the nearest tenth. Please help me with this. Thanks

Algebra ->  Trigonometry-basics -> SOLUTION: The problem states - Given J (-3,4) and K (-7, -2), find the magnitude of JK to the nearest tenth. Please help me with this. Thanks      Log On


   

Question 303195: The problem states - Given J (-3,4) and K (-7, -2), find the magnitude of JK to the nearest tenth.
Please help me with this.
Thanks
Found 2 solutions by nerdybill, nyc_function:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
The problem states - Given J (-3,4) and K (-7, -2), find the magnitude of JK to the nearest tenth.
.
You would apply the "distance formula":
d+=+sqrt%28%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%29+
.
The two points:(-3,4) and (-7, -2)
d+=+sqrt%28%28-7%2B3%29%5E2%2B%28-2-4%29%5E2%29+
d+=+sqrt%28%28-4%29%5E2%2B%28-6%29%5E2%29+
d+=+sqrt%2816%2B36%29+
d+=+sqrt%2852%29+
.
Oh, I guess they want the answer to the nearest tenth:
d = 7.2

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
I assume you are talking about vectors.
Let |JK| = the magnitude that we are seeking.
We use the distance formula.
|JK| = sqrt{(-7 -(-3))^2 + (-2 - 4)^2}
|JK| = sqrt{(-7 + 3)^2 + (-6)^2}
|JK| = sqrt{(-4)^2 + 36}
|JK| = sqrt{16 + 36}
|JK| = sqrt{52}
|JK| = 7.2111102551
We round this decimal to the tenths place and get
|JK| = 7.2