SOLUTION: please help me solve this equation; log(base 6)3x + log(base 6)(x-1) = 3

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Question 303095: please help me solve this equation;
log(base 6)3x + log(base 6)(x-1) = 3
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
log%286%2C3x%29+%2B+log%286%2C%28x-1%29%29+=+3
log%286%2C%283x%29%28x-1%29%29+=+3
%283x%29%28x-1%29+=+6%5E3
3x%5E2-3x+=+216
3x%5E2-3x-216+=+0
x%5E2-x-72+=+0
%28x%2B8%29%28x-9%29+=+0
x ={-7, 9}
But -7 is an extraneous solution, throw it out... leaving
x = 9