Question 303094: solve three times the smaller of two consecutive integers is added to four times the larger, the result is 67. find the smaller integer. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the smaller number be x
the next number will be x+1
3 times x= 3x
4 times larger number = 4(x+10
3x+4(x+1)=67
3x+4x+4=67
7x=67-4
7x=63
x= 9
the next number is 10