SOLUTION: PLEASE HELP ME A rocket is fired with an initial velocity of 800 meters per second. When will it be 32000 meters above the starting point? Than answer I got was : 40 second bec

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Question 30301: PLEASE HELP ME A rocket is fired with an initial velocity of 800 meters per second. When will it be 32000 meters above the starting point?
Than answer I got was : 40 second because I divided... I think its wrong thought
Answer by venugopalramana(3286) About Me  (Show Source):
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PLEASE HELP ME A rocket is fired with an initial velocity of 800 meters per second. When will it be 32000 meters above the starting point?
Than answer I got was : 40 second because I divided... I think its wrong thought
AS THE ROCKET GOES UP AGAINST EARTHS GRAVITATIONAL FORCE , ITS VELOCITY REDUCES,GIVEN BY ACCELERATION DUE TO GRAVITY =-9.8 M/SEC^2..THE FORMULA TO BE USED IS
S = UT + (G/2)T^2....WHERE
U = INIYIAL VELOCITY = 800 M/SEC
T = TIME ELAPSED IN SECS.
G=ACCELERATION DUE TO GRAVITY = - 9.8 M/SEC^2 FOR UPWARD TRAVEL...SO..WE GET
32000 = 800T -(9.8/2)T^2=800T-4.9 T^2
4.9T^2-800T+32000 =0
t+=+%28800+%2B-+sqrt%28+800%5E2-4%2A4.9%2A32000+%29%29%2F%282%2A4.9%29+
T=70.1 WHILE GOING UP AND
T=93.2 WHILE FALLING DOWN.