SOLUTION: PLEASE EXPLAIN TO ME HOW TO FIND C^2=1305 THE QUESTION IS IF A=24 AND B=27 THEN WHAT IS C? C^2=(24)^2+(27)^2 c^2=576+729 C^2=1305 SO C=WHAT

Algebra ->  Formulas -> SOLUTION: PLEASE EXPLAIN TO ME HOW TO FIND C^2=1305 THE QUESTION IS IF A=24 AND B=27 THEN WHAT IS C? C^2=(24)^2+(27)^2 c^2=576+729 C^2=1305 SO C=WHAT      Log On


   

Question 30293: PLEASE EXPLAIN TO ME HOW TO FIND C^2=1305
THE QUESTION IS IF A=24 AND B=27 THEN WHAT IS C?
C^2=(24)^2+(27)^2
c^2=576+729
C^2=1305
SO C=WHAT
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
if c%5E2+=+1305 then c has 2 possible values, either sqrt%281305%29 or -sqrt%281305%29.

Either use your calculator to find the decimal version of this number, which you will have to round up. Hence it will not be the precise answer, merely an approximation --> 36.125 to 5 significant figures.

Alternatively, leave it in radical form, but simplify the number if you can. In this example, we can, since 9 goes into 1305.

+sqrt%281305%29+
+sqrt%289%2A145%29+
+sqrt%289%29sqrt%28145%29+
+3sqrt%28145%29+

So the EXACT answers are +3sqrt%28145%29+ and -+3sqrt%28145%29+

Jon.