SOLUTION: Smith travels 45 miles going East from the center of the town and Jones travels 70 miles going West from the same point. If Jones averages 5 miles per hour more than Smith and his

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Question 302429: Smith travels 45 miles going East from the center of the town and Jones travels 70 miles going West from the same point. If Jones averages 5 miles per hour more than Smith and his trip took ½ hour longer than Smith’s. How fast was each of them traveling?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let s = Smith's speed
Then s+%2B+5 = Jone's speed
Let t = Smith's time
Then t+%2B+.5 = Jone's time
Write an equation for each one
For Smith:
45+=+s%2At
t+=+45%2Fs
For Jones:
70+=+%28s+%2B+5%29%2A%28t+%2B+.5%29
This is 2 equations and 2 unknowns, so it's solvable
70+=+s%2At+%2B+5t+%2B+.5s+%2B+2.5
by substitution:
70+=+45+%2B+5t+%2B+.5s+%2B+2.5
by substitution again:
25+=+5%2A%2845%2Fs%29+%2B+.5s+%2B+2.5
25+-+2.5+=+225%2Fs+%2B+.5s
Multiply both sides by s
22.5s+=+225+%2B+.5s%5E2
Multiply both sides by 10
225s+=+2250+%2B+5s%5E2
5s%5E2+-+225s+%2B+2250+=+0
s%5E2+-+45s+%2B+450+=+0
Use quadratic formula
s+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a+=+1
b+=+-45
c+=+450
s+=+%28-%28-45%29+%2B-+sqrt%28+%28-45%29%5E2-4%2A1%2A450+%29%29%2F%282%2A1%29+
s+=+%2845+%2B-+sqrt%282025+-+1800+%29%29%2F2+
s+=+%2845+%2B-+sqrt%28225%29%29%2F2+
s+=+%2845+%2B-+15%29%2F2+
s+=+30
s+=+15
There's a choice of 2 answers. I'll try
s+=+30
s+%2B+5+=+35
check:
45+=+s%2At
t+=+45%2F30
t+=+1.5 hrs
and
70+=+%28s+%2B+5%29%2A%28t+%2B+.5%29
70+=+%2830+%2B+5%29%2A%28t+%2B+.5%29
t+%2B+.5+=+70%2F35
t+=+2+-+.5
t+=+1.5 hrs
t+%2B+.5+=+2 hrs
----------------------
also:
s+=+15
s+%2B+5+=+20
check:
45+=+s%2At
t+=+45%2F15
t+=+3
70+=+%28s+%2B+5%29%2A%28t+%2B+.5%29
70+=+%2815+%2B+5%29%2A%28t+%2B+.5%29
70%2F20+=+t+%2B+.5
t+=+3.5+-+.5
t+=+3 hrs
t+%2B+.5+=+3.5 hrs
There are 2 possibilities:
(1)
Smith traveled 30 mi/hr
Jones traveled 35 mi/hr
(2)
Smith traveled 15 mi/hr
Jones traveled 20 mi/hr