SOLUTION: 27a^7 b^6 / 9a^8 b^5 = this is a division problem that I need help with. ^=to the power of.

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Question 301903: 27a^7 b^6 / 9a^8 b^5 =
this is a division problem that I need help with. ^=to the power of.
Found 2 solutions by helpnalgebra, london maths tutor:
Answer by helpnalgebra(91) About Me  (Show Source):
You can put this solution on YOUR website!
(27a^(7)b^(6))/(9)*a^(8)b^(5)
Reduce the expression (27a^(7)b^(6))/(9) by removing a factor of 9 from the numerator and denominator.
3a^(7)b^(6)*a^(8)b^(5)
Multiply 3a^(7)b^(6) by a^(8)b^(5) to get 3a^(15)b^(11).
3a^(15)b^(11)answer

Answer by london maths tutor(243) About Me  (Show Source):
You can put this solution on YOUR website!
27a^7 b^6 / 9a^8 b^5
= (27/9)*(a^7/a^8)*(b^6/b^5)
= 3*(1/a)*(b)
= 3b/a