SOLUTION: Dimensions of a triangle. A triangle is 10 cm wider
than it is tall. The area 48 cm^2 is Find the height and
the base.
my teacher said my equation is not right because of the fo
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-> SOLUTION: Dimensions of a triangle. A triangle is 10 cm wider
than it is tall. The area 48 cm^2 is Find the height and
the base.
my teacher said my equation is not right because of the fo
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Question 301799: Dimensions of a triangle. A triangle is 10 cm wider
than it is tall. The area 48 cm^2 is Find the height and
the base.
my teacher said my equation is not right because of the formula i am using can someone help me Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Dimensions of a triangle.
A triangle is 10 cm wider than it is tall.
The area 48 cm^2 is Find the height and the base
:
Let x = the height
then
(x+10) = the base
:
Area of a triangle *b*h = A
in this problem *(x+10)*x = 48 *(x^2 +10x) = 48
multiply both sides by 2, to get rid of the fraction, results
x^2 + 10x = 96
A quadratic equation
x^2 + 10x - 96 = 0
Factors to
(x+16)(x-6) = 0
positive solution
x = 6 is the height
and obviously, 16 = the base
:
Check your solution in the Area of a triangle equation
