SOLUTION: {{{(x+2)(x+4)=20+10(x)}}}i get stuck on this problem what are the consecutive even integers ? i did FOIL for the first half and the x times ten and got {{{x^2+4x+2x+8=20+10x}}} the

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: {{{(x+2)(x+4)=20+10(x)}}}i get stuck on this problem what are the consecutive even integers ? i did FOIL for the first half and the x times ten and got {{{x^2+4x+2x+8=20+10x}}} the      Log On


   

Question 301585: %28x%2B2%29%28x%2B4%29=20%2B10%28x%29i get stuck on this problem what are the consecutive even integers ? i did FOIL for the first half and the x times ten and got x%5E2%2B4x%2B2x%2B8=20%2B10x then combined like terms and got x%5E2%2B6x%2B8=20%2B10x
then i subtracted 6x from both sides and got x%5E2%2B8=20%2B4x. then i subract 8 from both sides, and get x%5E2=12%2B4x. plese help me solve this question.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(x+2)(x+4)=20+10(x)
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i get stuck on this problem what are the consecutive even integers ? i did FOIL for the first half and the x times ten and got x%5E2%2B4x%2B2x%2B8=20%2B10x then combined like terms and got
x^2+6x+8=20+10x
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Subtract 20+10x from both sides to get:
x^2 -4x - 12 = 0
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Factor:
x^2 - 6x + 2x -12 = 0
x(x-6) + 2(x-6) = 0
(x-6)(x+2) = 0
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x = 6 or x = -2
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cheers,
Stan H.