SOLUTION: a bag contains 4 red, 5 white, and 3 blue marbles. Find the probability of obtaining a red or white marble in a single draw. compute the mean, the 5% trimmed mean, and the 10% t

Algebra ->  Probability-and-statistics -> SOLUTION: a bag contains 4 red, 5 white, and 3 blue marbles. Find the probability of obtaining a red or white marble in a single draw. compute the mean, the 5% trimmed mean, and the 10% t      Log On


   



Question 301427: a bag contains 4 red, 5 white, and 3 blue marbles. Find the probability of obtaining a red or white marble in a single draw.
compute the mean, the 5% trimmed mean, and the 10% trimmed mean for the scores. Be sure to label which is which round to the nearest tenth, if necessary.
56.46,88,50,65,56,77,79,100,70,66,14,72,51,52,53,84,57,83,68. show your work

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4 R, 5 W, 3 B=12 total
P(R)=4/12=1/3
P(W)=5/12
P(R or W)=P(R)+P(W)=9/12=3/4
.
.
.
I assume you meant 56, 46 and not 56.46.
Mean = 64.4
"5% trimmed mean" by definition means taking 2.5% values from top and 2.5% value from bottom and then re-taking the mean. Since there are 20 values, 5% is 1 value. I'll assume you mean 10% trimmed mean and 20% trimmed mean.
5% trimmed mean (take out 14 and 100) = 65.2
10% trimmed mean (take out 14,46,88, and 100) = 64.9