SOLUTION: A 60% acid solution is to be mixed with a 80% acid solution to produce 20 Liters of a 65% acid solution. How many liters of each solution is needed?

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Question 301358: A 60% acid solution is to be mixed with a
80% acid solution to produce 20 Liters of a
65% acid solution. How many liters of each
solution is needed?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let a = liters of 60% solution needed
Let b = liters of 80% solution needed
given:
(1) a+%2B+b+=+20 liters
.6a+%2B+.8b+=+.65%2A20
.6a+%2B+.8b+=+13
(2) 6a+%2B+8b+=+130
Multiply both sides of (1) by 6 and subtract (1) from (2)
6a+%2B+8b+=+130
-6a+-+6b+=+-120
2b+=+10
b+=+5
and, since
a+%2B+b+=+20
a+%2B+5+=+20
a+=+15
15 liters of 60% solution and 5 liters of 80% solution are needed
check:
In words:
(liters of acid you end up with) / (final total liters of solution) = 65%
%28.6%2A15+%2B+.8%2A5%29%2F20+=+.65
9+%2B+4+=+.65%2A20
13+=+13
OK