SOLUTION: How do you solve: using substitution 5x-2y=-7 8=y-4x

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Question 301316: How do you solve: using substitution
5x-2y=-7
8=y-4x

Found 2 solutions by richwmiller, Stitch:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
first you have to rearrange the second.
4x+8=y
now plug 4x+8 for y in the first
5x-2*(4x+8)=-7
5x-8x-16=-7
-3x=9
x=-3
now plug that into the second and solve for y
8=y-4*(-3)
8=y+12
-4=y
(x,y)=(-3,-4)

Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Set-Up:
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Equation 1: 5X+-+2Y+=+-7
Equation 2: 8+=+Y+-+4X
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Solution:
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You need to solve one of the equations for one variable. in this case I thin that solving equation 2 for Y is the easiest.
Equation 2: 8+=+Y+-+4X Add 4X to both sides
8+%2B+4X+=+Y
Now you can plug (8 + 4X) into equation 1 for Y
Equation 1: 5X+-+2Y+=+-7
5X+-+2%2A%288+%2B+4X%29+=+-7 Simplify
5X+-+16+-+8X+=+-7 Simplify
-3X+-+16+=+-7 Add 16 to both sides
-3X+=+9 Divide both sides by -3
highlight%28X+=+-3%29
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Now plug -3 into equation 2 for X
8+%2B+4X+=+Y
8+%2B+4%2A%28-3%29+=+Y
8+-+12+=+Y
highlight_green%28-4+=+Y%29