SOLUTION: 20x^2-82x+80=0

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Question 301307: 20x^2-82x+80=0
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
20x%5E2-82x%2B80+=+0 First factor 2.
2%2810x%5E2-42x%2B40%29+=+0 so that...
10x%5E2-41x%2B40+=+0 Factor the trinomial.
%282x-5%29%285x-8%29+=+0 Apply the zero product rule.
2x-5+=+0 or 5x-8+=+0
2x+=+5 or 5x+=+8
highlight%28x+=+5%2F2%29 or highlight%28x+=+8%2F5%29