SOLUTION: Trains A and B are traveling in the same diection on parallel tracks. A is traveling at 80 miles per hour and train B is traveling at 100 mile per hour .Train A passes the station

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Trains A and B are traveling in the same diection on parallel tracks. A is traveling at 80 miles per hour and train B is traveling at 100 mile per hour .Train A passes the station       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 301290: Trains A and B are traveling in the same diection on parallel tracks. A is traveling at 80 miles per hour and train B is traveling at 100 mile per hour .Train A passes the station at 5:15am .If train B passs the same station at 5:27 a.m.at what time will train be catch at to train A. When will train b catch up with train A?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Trains A and B are traveling in the same diection on parallel tracks.
A is traveling at 80 miles per hour and train B is traveling at 100 mile per hour Train A passes the station at 5:15am .
If train B passes the same station at 5:27 a.m. at what time will train B catch at to train A.
When will train B catch up with train A?
:
from the given information, we know that train B is 12 min (1/5 hr) behind
train A, when train A passes the station
:
The distance between the trains at this time: 1%2F5 * 100 = 20 mi
:
Let t = time required for train B to catch train A
:
write a distance equation: Dist = speed * time
:
Train B travel dist = Train A travel dist + 20 mi
100t = 80t + 20
100t - 80t = 20
20t = 20
t = 20%2F20
t = 1 hr
:
5:15 + 1:00 = 6:00 AM, B catches A