SOLUTION: Algebra II...Word problem: Joe is 10 years older than James. In 8 years, twice Joe's age will will equal 3 times Jame's age. How old is each now?....Nick

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Algebra II...Word problem: Joe is 10 years older than James. In 8 years, twice Joe's age will will equal 3 times Jame's age. How old is each now?....Nick      Log On


   

Question 301110: Algebra II...Word problem:
Joe is 10 years older than James. In 8 years, twice Joe's age will will equal 3 times Jame's age. How old is each now?....Nick
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let james age be x
Joe will be x+10
after 8 years their ages will be
x+8 & x+10+8
3(x+8) = 2(x+18)
3x+24=2x+36

x=12 jame's age
joe's age = x+10 = 22