SOLUTION: We learned how to factor trinomials awhile ago, by unfoiling like {{{x^2+2x-3}}} would be (x+3)(x-1), but how do you do it if there is a coefficient in front of the {{{x^2}}} like

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: We learned how to factor trinomials awhile ago, by unfoiling like {{{x^2+2x-3}}} would be (x+3)(x-1), but how do you do it if there is a coefficient in front of the {{{x^2}}} like       Log On


   



Question 300802: We learned how to factor trinomials awhile ago, by unfoiling like x%5E2%2B2x-3 would be (x+3)(x-1), but how do you do it if there is a coefficient in front of the x%5E2 like 3b%5E2-17b%2B22 i used to just factor it out when they were simple bye just making like 2x%5E2%2B4x%2B6 into 2%28x%5E2%2B2x%2B3%29 but it dosent work like that anymore because im getting ugly decimals. Please help.
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Given: 3B%5E2+-+17B+%2B+22
You still use the unfoil method however you need to include the coefficient.
Find the factors of 22: 1,2,11,22
You need to look at those factors and figure out how to get -17 while using the coefficient with one of the factors.
-17 = -11 - 3*(2)
%283B+-+11%29%2A%28B+-+2%29+=+3B%5E2+-+17B+%2B+22
Set that equal to 0 to solve for B
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3B+-+11+=+0
3B+=+11
highlight%28B+=+11%2F3%29 or 3.6667
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B+-+2+=+0
highlight_green%28B+=+2%29