SOLUTION: Suppose f(x)=3x-6, g(x)=x^2 + square root of x, and h(x) = x/3 + 2 What is: f(g(4))

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Suppose f(x)=3x-6, g(x)=x^2 + square root of x, and h(x) = x/3 + 2 What is: f(g(4))      Log On


   

Question 300696: Suppose f(x)=3x-6, g(x)=x^2 + square root of x, and h(x) = x/3 + 2
What is: f(g(4))
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=3x-6
g%28x%29=x%5E2+%2B+sqrt%28x%29
h%28x%29+=+x%2F3+%2B+2
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g%284%29=4%5E2%2Bsqrt%284%29
g%284%29=16%2B2=18 (Note:sqrt%284%29 could also be -2 so then g%284%29=14)
g%284%29=18
f%28g%284%29%29=f%2818%29=3%2818%29-6
f%28g%284%29%29=54-6
f%28g%284%29%29=48