SOLUTION: ln(5x-6)+ln(x-4)=ln24 how do i solve this ?

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Question 300335: ln(5x-6)+ln(x-4)=ln24 how do i solve this ?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
ln(5x-6)+ln(x-4) = ln(24)
Adding logs is multiply
ln((5x-6)(x-4)) = ln (24)
FOIL
ln(5x^2 - 20x - 6x + 24) = ln(24)
ln(5x^2 - 26x + 24) = ln(24)
therefore
5x^2 - 26x + 24 = 24
5x^2 - 26x + 24 - 24 = 0
5x^2 - 26x = 0
x(5x - 26) = 0
x = 0, not a solution obviously, can't have ln of negative number
and
5x = 26
x = 26%2F5
x = 5.2
:
:
Check solution x=5.2 in original problem
ln(5(5.2)-6)+ln(5.2-4) = ln(24)
ln(26-6)+ln(1.2) = ln(24)
ln(20)+ln(1.2) = ln(24)
Check using a calc
2.9957 + .1823 = 3.178 ~