Question 300307: A bag contains five balls numbered 1,2,3,4,5. Another bag contains six balls numbered 1,2,3,4,5,6. One ball is drawn at random from each ball. Find the probability that (i) both balls have the same number.(ii) the sum of the numbers on the balls is 9.
Found 2 solutions by Fombitz, CharlesG2:
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! Make a table.
Bag 1 Bag 2 Sum
1 1 2
1 2 3
1 3 4
1 4 5
1 5 6
.
.
.
5 1 6
5 2 7
5 3 8
5 4 9
5 5 10
5 6 11
i) Then count the total number of outcomes.
There are 30 in all (5x6).
Then count the times that the ball from Bag 1 is the same as Bag 2.
There are 5 of those (1-1,2-2,3-3,4-4,5-5).
So the probability of two balls identical is
P=5/30=1/6
ii) Count the number of sums that equal 9.
There are 3 outcomes (3-6,4-5,5-4).
There are 30 total outcomes.
P=3/30=1/10
Answer by CharlesG2(834)  (Show Source):
You can put this solution on YOUR website! A bag contains five balls numbered 1,2,3,4,5. Another bag contains six balls numbered 1,2,3,4,5,6. One ball is drawn at random from each ball. Find the probability that (i) both balls have the same number.(ii) the sum of the numbers on the balls is 9.
wait one ball is drawn at random from each ball? what? I am thinking you mean bag, so I will continue thinking you mean that...
one bag has 5 balls numbered 1 to 5
the other bag has 6 balls numbered 1 through 6
1/5 and 1/6 respectively for a particular ball
1/5 * 1/6 = 1/30 for the same number and 5 possibilities
so 5 * 1/30 = 5/30 = 1/6
3 possibilities to get the sum of the numbers on the balls to be 9
3 + 6 = 9 --> 1/5 * 1/6 = 1/30
4 + 5 = 9 --> 1/5 * 1/6 = 1/30
5 + 4 = 9 --> 1/5 * 1/6 = 1/30
3 possibilities --> 1/30 + 1/30 + 1/30 = 3/30 = 1/10
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