SOLUTION: 1. Simplify. log(4) 4^2 2. Express as a product. log(b) t^8 3. Express as a difference of logarithms. log(g) M/4 4. Rewrite as an equivalent exponential equ

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: 1. Simplify. log(4) 4^2 2. Express as a product. log(b) t^8 3. Express as a difference of logarithms. log(g) M/4 4. Rewrite as an equivalent exponential equ      Log On


   

Question 300300: 1. Simplify.
log(4) 4^2

2. Express as a product.
log(b) t^8

3. Express as a difference of logarithms.
log(g) M/4

4. Rewrite as an equivalent exponential equation. Do not solve.
log(10) 18=1.2553
Found 2 solutions by stanbon, CharlesG2:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1. Simplify.
log(4) 4^2 = 2
---------------------
2. Express as a product.
log(b) t^8 = 8*logb(t)
---------------------------
3. Express as a difference of logarithms.
log(g) M/4 = logg(M) - logg(4)
---------------------------
4. Rewrite as an equivalent exponential equation. Do not solve.
log(10) 18=1.2553
---
10^1.2553 = 18
==================
Cheers,
Stan H.
==================

Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
1. Simplify.
log(4) 4^2
logb (m^n) = nlogb m
log4 4^2 = 2log4 4 = 2 * 1 = 2
2. Express as a product.
log(b) t^8
8logb t
3. Express as a difference of logarithms.
log(g) M/4
logb (m/n) = logb m - logb n
log(g) (M/4) = log(g) M - log(g) 4
4. Rewrite as an equivalent exponential equation. Do not solve.
log(10) 18=1.2553
logb y = x
b^x = y
log(10) 18=1.2553 --> 10^(1.2553) = 18