SOLUTION: The equation (((h=-16^2-32t+320))), gives the height of a ball, thrown downward from the top of a 320ft building with an initial velocity of 32ft/sec. Find the time it takes for th

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: The equation (((h=-16^2-32t+320))), gives the height of a ball, thrown downward from the top of a 320ft building with an initial velocity of 32ft/sec. Find the time it takes for th      Log On

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Question 30016: The equation (((h=-16^2-32t+320))), gives the height of a ball, thrown downward from the top of a 320ft building with an initial velocity of 32ft/sec. Find the time it takes for the ball to reach a height 160ft. Heres what I have so far, h=160, 160=16t^2+32t+320,160=0,16t^2+32t-320=0,divide by 16,
leaving t^2+2t-20, using the quadratic formula t=b(+or-)radical sign (-2)^2-4(1)(20)/2=0, 2(+or-)radical sign 4+80/2, so the answer I get is 2+ radical sign,84/2, and 2- radical sign 84/2. My math book says the answer is 2.317seconds, but does not show how to get there. Thanks,

Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
I see your first mistake ...
+160=16t%5E2%2B32t-320+ subtract 160 from both sides
+0+=+16t%5E2%2B32t-highlight%28160%29+ You left it as 320
simple little mistakes like that will kill you.
+0+=+16t%5E2%2B32t-160+ divide by 16
+0+=+t%5E2+%2B+2t+-+10+ use the quadratic ...
+x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
+x+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A1%2A%28-10%29+%29%29%2F%282%2A1%29+
+x+=+%28-2+%2B-+sqrt%28+4-4%2A1%2A%28-10%29+%29%29%2F%282%2A1%29+
+x+=+%28-2+%2B-+sqrt%28+4%2B40+%29%29%2F%282%29+
+x+=+%28-2+%2B-+sqrt%28+44+%29%29%2F%282%29+
+x+=+%28-2+%2B-+2sqrt%28+11+%29%29%2F%282%29+ divide by 2
+x+=+%28-1+%2B-+1sqrt%28+11+%29%29+ assuming ONLY the possitive root ...
+x+=+%28-1+%2B+1sqrt%28+11+%29%29+ root out 11 = 3.31662 ......
+x+=+-1+%2B+3.31662+
+x+=+2.317+ rounded to the nearest thousandth