Question 300075: I'm lost here, my brain is on the blink today can somebody help me with this one. I would greatly appreciated any help on solving this problem.
You are given the following data. Test the claim that there is a difference in the means of the two groups. Use = 0.05.
Group A Group B
= 10 = 2
= 1.0 = 0.1
= 99 = 52
•State the null and alternate hypotheses
•Determine which test statistic applies, and calculate it
•Determine the critical value(s).
•State your decision: Should the null hypothesis be rejected?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Test the claim that there is a difference in the means of the two groups. Use = 0.05.
Group A Group B
= 10 = 2
= 1.0 = 0.1
= 99 = 52
-----
ua = (10+1+99)/3 = 110/3 36.67
sa^2 = 17.57^2
na = 3
---
ub = (2+0.1+52)/3 = 54.1/3 = 18.03
sb^2 = 7^2
nb = 3
----------------------------------------
•State the null and alternate hypotheses
Ho: ua-ub = 0
Ha: ua-ub is not equal to zero
-------------------------------------------
•Determine which test statistic applies, and calculate it
t = (36.67-18.03)/sqrt[(17.57^2/3 = 7^2/3] = 3.1313
-----
•Determine the critical value(s).
invT(0.975,2) = +-4.3027
------
•State your decision: Should the null hypothesis be rejected?
The test stat is not in either reject interval.
Fail to reject Ho.
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Cheers,
Stan H.
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