SOLUTION: If a ball is thrown vertically upward from the roof of a 32 foot tall building with a velocity of 64 ft/sec, its height in feet after T seconds is: s(T)= 32+64T-16T^2
What is t
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What is t
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Question 300037: If a ball is thrown vertically upward from the roof of a 32 foot tall building with a velocity of 64 ft/sec, its height in feet after T seconds is: s(T)= 32+64T-16T^2
What is the maximum height the ball reaches?
What is the velocity of the ball when it hits the ground (height )? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! s(T)= 32+64T-16T^2
What is the maximum height the ball reaches?
Find t for the vertex of the parabola:
It's at t = -b/2a = -64/-32 = 2 seconds
s(2) = 32 + 128 - 64 = 96 feet
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What is the velocity of the ball when it hits the ground (height )?
The ball falls from 96 feet, starting with v = 0
s = 16t^2 = 96
t^2 = 6
t = sqrt(6) seconds
a = acceleration = 32 ft/sec/sec
v = at = 32sqrt(6)
v =~ 78.38 ft/sec
