SOLUTION: Okay I had a problem on a test for Intermediate Algebra- I had to find all 3 angles in degrees for a triangle. The problem was that the smaller angle is half of the larger angl

Click here to see ALL problems on Triangles

Question 2999: Okay I had a problem on a test for Intermediate Algebra-
I had to find all 3 angles in degrees for a triangle.
The problem was that the smaller angle is half of the larger angle and that the second angle is 25 degrees less than the larger angle.
What is the measure of the larger angle? (and other angles)
Thanks for anyone who can key me in here...I got something completley wrong
x1 (smaller angle)= 28 degrees
x2 (medium angle)= 68 degrees
x3 (larger angle)= 84 degrees
But my answer is all wrong because 68 is not 25 less than 84 and 28 is not half of 84....so very confused =/

Found 2 solutions by longjonsilver, cleomenius:
Answer by longjonsilver(2297) (Show Source):
You can put this solution on YOUR website!
first define one of the angles to be a variable:

let's say the smallest angle is x...

so, middle angle = 2x
and largest angle = 2x + 25

And all 3 angles add up to 180.

So, x + 2x + 2x+25 = 180
5x + 25 = 180
5x = 155
x = 31

so 3 angles are 31, 62, 87...which do add up to 180 degrees!

OK?

jon.

Answer by cleomenius(959) (Show Source):
You can put this solution on YOUR website!
Angle 1 = x
Angle 2 = 2x
Angle 3 = 2x - 25
==========================
x + 2x + 2x - 25 = 180
5x = 205
x = 41 degrees = angle 1.
2x = 82 degrees = angle 2.
2x - 25 = 57 degrees = angle 3.
Cleomenius.