SOLUTION: 2) Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. The formula for the perimeter of a rectangle is

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Question 299862: 2) Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches. The formula for the perimeter of a rectangle is P=2L+2W.
a) Set up an equation for the perimeter involving only L, the length of the rectangle.
Answer:
b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
Answer: Length ______, Width ______
Show your work here:
Answer by unlockmath(1688) (Show Source):
You can put this solution on YOUR website!
Hello,
Let's show width as L-5 then we can set up this equation as:
2(L-5)+2L=50 Combine like terms to get:
4L-10=50 Add 10 and divide 4 to get:
L=15 inches
So now we know the width is 10 inches.
Make sense?
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