SOLUTION: 4x^2-8x+1=0

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Question 299757: 4x^2-8x+1=0
Answer by checkley77(12844) About Me  (Show Source):
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4x^2-8x+1=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(8+-sqrt[-8^2-4*4*1])/2*4
x=(8+-sqrt64-16)/8
x=(8+-sqrt48)/8
x=(8+-6.9282)/8
x=(8+6.9282)/8
x=14.9282)/8
x=1.866 ans.
x=(8-6.9282)/8
x=1.0718/6
x=.134 ans.