SOLUTION: (3x to the 5th)3(2x to the 7th)2

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Question 299747: (3x to the 5th)3(2x to the 7th)2
Answer by Alan3354(69443) About Me  (Show Source):
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(3x to the 5th)3(2x to the 7th)2
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%283x%5E5%29%5E3+%2A+%282x%5E7%29%5E2
Expand each term
= 27x%5E15+%2A+4x%5E14
Multiply the coefficients and add the exponents
= 108x%5E29