SOLUTION: 7. A 25% solution of alcohol is to mixed with a 40% solution to get 50 litres of a final mixture that is 30% alcohol. How much of each of the original s
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: 7. A 25% solution of alcohol is to mixed with a 40% solution to get 50 litres of a final mixture that is 30% alcohol. How much of each of the original s
Log On
Question 299733: 7. A 25% solution of alcohol is to mixed with a 40% solution to get 50 litres of a final mixture that is 30% alcohol. How much of each of the original solutions should be used? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .40x+.25(50-x)=.30*50
.40x+12.5-.25x=15
.15x=15-12.5
.15x=2.5
x=2.5/.15
x=16.667 Liters of 40% solution is used.
50-16.667=33.333 Liters of 25% solution is used.
Proof:
.40*16.667+,25*33.333=.30*50
6.667+8.333=15
15=15