SOLUTION: tim paddled his kayak 12 km upstream against a 3km/h current and back again in 5 hours and 20 minutes. IN that time how far could he have paddled in still water?

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Question 29959: tim paddled his kayak 12 km upstream against a 3km/h current and back again in 5 hours and 20 minutes. IN that time how far could he have paddled in still water?
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Let the speed of the boat in still water be x
Against = -
"back again" = +
5hours and 20 minutes =5 1/3--->16/3

Equation;
12%28x-3%29=%2816%28x%2B3%29%29%2F3
Expand:
12x-36=%2816x%2B48%29%2F3
Multiply the whole equation by 3 to remove the fraction:
3%28%2812x-36%29%2F1%29=3%28%2816x%2B48%29%2F3%29





Hence, the speed of the boat is 7.8mph in the still water.
Paul.