Question 29920: Please solve for x:
2x^2=7x-3
and
x^2-5cx+6c^2=0
Answer by z_2007(1)   (Show Source):
You can put this solution on YOUR website! First problem:
 You want to start out by getting everything to one side, so subtract 7x from both sides and add 3 to both sides.
 Then factor this and you come up with  . Set each part equal to 0.  and  . Solve for x in each.
Add 1 to both sides.
 Divide each side by 2.
 AND
Add 3 to both sides.
 So your two answers are and
Second problem:
 Everything is already to one side, and it equals 0, so it is ready to factor. You factor this very similarly to how you would factor a question without the extra variable. The only way to come up with x^2 is to multiply x and x, so you k now that is the first part.
Then you figure out what two numbers when multiplied equal 6 and when added together equal -5. Factors of 6 are 1 and 6, 2 and 3. 2 and 3 could equal -5 if both were negative, and if you multiplied -2 and -3 you would still get a positive 6, so you can start filling in the parenthesis.
 If the variable c was not in the equation you would be done factoring, but we still have another variable. Like the x^2, the only way to get c^2 is to multiply c and c, so that goes in the parenthesis like this:
Now set both parts equal to 0 and solve for x.
 Add 2c to both sides.
 this tells you what x is equal to, and is as far as you can go with the information given. This is one part of the answer.
 Add 3c to both sides.
 This is the other part of your answer.
|
|
|
