Question 299119: A chemist has 6L of 50 % acid solution. how much water to be added to obtain 20% acid solution? Found 2 solutions by checkley77, Alan3354:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! .50*6=.20(6+x)
3=1.2+.2x
.2x=3-1.2
.2x=1.8.
x=1.8/.2
x=9 Liters of water is needed.
Proof:
.50*6=.20(6+9)
3=.2*15
3=3
You can put this solution on YOUR website! The 6 liters of 50% is 3 liters of acid and 3 liters of water.
To make it a 20% mix, water will be the other 80%.
3 liters of acid = 20%
12 liters of water = 80%
12 - 3 = 9 liters of water to be added.
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