SOLUTION: The work surface of Anita's desk is a rectangle that is
twice as long as it is wide. If the area of the desk is
18ft^2, find the length and width of the desk.
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-> SOLUTION: The work surface of Anita's desk is a rectangle that is
twice as long as it is wide. If the area of the desk is
18ft^2, find the length and width of the desk.
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Question 299117: The work surface of Anita's desk is a rectangle that is
twice as long as it is wide. If the area of the desk is
18ft^2, find the length and width of the desk. Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! The work surface of Anita's desk is a rectangle that is
twice as long as it is wide. If the area of the desk is
18ft^2, find the length and width of the desk.
.
Let w = width
then
2w = length
.
w(2w) = 18
2w^2 = 18
w^2 = 9
w = 3 feet (width)
.
Length
2w = 2(3) = 6 feet (length)
