SOLUTION: Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hour less than the other's. If they meet in 3 hours, wh

Algebra ->  Inequalities -> SOLUTION: Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hour less than the other's. If they meet in 3 hours, wh      Log On


   

Question 299054: Two cars leave towns 480 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
D=RT
480=[(R-12)+R]3
480=(2R-12)3
480=6R-36
6R=480+36
6R=516
R=516/6
R=86 KMH IS THE SPEED OF THE FASTER CAR.
86-12=74KMH IS THE SPEED OF TH SLOWER CAR.
PROOF:
480=(74+86)3
480=160*3
480=480