SOLUTION: Each hour, a wood-harvesting machine cuts the same number of logs and places them on a pile. At 8 am, there are 13 logs on the pile. At 11 am, the pile has grown to 46 logs. How m

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Each hour, a wood-harvesting machine cuts the same number of logs and places them on a pile. At 8 am, there are 13 logs on the pile. At 11 am, the pile has grown to 46 logs. How m      Log On

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Question 298980: Each hour, a wood-harvesting machine cuts the same number of logs and places them
on a pile. At 8 am, there are 13 logs on the pile. At 11 am, the pile has grown to 46 logs. How many logs will the pile contain at 6 pm?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Each hour, a wood-harvesting machine cuts the same number of logs and places them on a pile.
At 8 am, there are 13 logs on the pile.
At 11 am, the pile has grown to 46 logs.
How many logs will the pile contain at 6 pm?
----
You have two points: (0,13), where 0 represents 8am,
and (3,46), where 3 represents 11am.
----
Equation ?
slope = (46-13)/(3-0) = 11
intercept = 13
----------------------
f(x) = 11x + 13 where x is the # of hours after 8am
----
How many logs will the pile contain at 6 pm?
At 6pm, x = 10
f(10) = 11*10 + 13
f(10) = 126 (# of logs at 6pm)
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Cheers,
Stan H.