SOLUTION: I need help finding the point of intersection for 6x-2y=10, and 3x-5=y.

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Question 29896: I need help finding the point of intersection for 6x-2y=10, and 3x-5=y.
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+6x-2y=10+ and +3x-5=y+ since the second equation is already solved for y I will use substitution.
+6x-2y=10+ plug in the second equation +3x-5+ for y
+6x-2%283x-5%29=10+ distribute the 2 watch your signs!!
+6x-6x%2B10=10+ combine like terms
+10+=+10+ We know this to be a true statement, but does not answer what the point of intersection is, so let's look at the first equation again.
+6x-2y=10+ all numbers are divisable by 2 ... lets divide.
+6x%2F2-2y%2F2=10%2F2+
+3x-5=y+ But that is the second equation. So that means that they are in fact the exact same line, and have an infinite number of solutions.