SOLUTION: Find all real solutions of the following equation:log[4]x+log [4] (x+12) = 3 Here are the possible solutions: (1) x=12 (2) x=4 (3) x= 16,12 (d) none of these

Algebra ->  College  -> Linear Algebra -> SOLUTION: Find all real solutions of the following equation:log[4]x+log [4] (x+12) = 3 Here are the possible solutions: (1) x=12 (2) x=4 (3) x= 16,12 (d) none of these       Log On


   

Question 29879: Find all real solutions of the following equation:log[4]x+log [4] (x+12) = 3
Here are the possible solutions:
(1) x=12
(2) x=4
(3) x= 16,12
(d) none of these
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
log[4]x+log [4] (x+12) = 3 when adding, you are really multiplying
log[4](x)(x+12) = 3
log [4] (x^2 + 12x) = 3
[4] is the base
3 is the power
x^2 + 12x is what they equal
+4%5E3+=+x%5E2+%2B+12x+
+64+=+x%5E2+%2B+12x+
+0+=+x%5E2+%2B+12x+-64+ factor
+0+=+%28x%2B16%29%28x-4%29+
+0+=+x%2B16+ or +0+=+x-4+
+-16+=+x+ or +4+=+x+