SOLUTION: I need help solving this equation! {{{ 4x^2(x-1)^(1/3) + 6x(x-1)^(4/3) = 0 }}} Please show me how to solve this step by step!

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Question 298710: I need help solving this equation!
+4x%5E2%28x-1%29%5E%281%2F3%29+%2B+6x%28x-1%29%5E%284%2F3%29+=+0+
Please show me how to solve this step by step!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I need help solving this equation!
4x^2(x-1)^(1/3) + 6x(x-1)^(4/3) = 0
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Factor:
2x(x-1)^(1/3)[2x + 3(x-1)] = 0
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Simplify:
2x(x-1)^(1/3)[5x-3] = 0
x = 0 or (x-1)^(1/3) = 0 or (5x-3) = 0
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x = 0 or x = 1 or x = 3/5
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Cheers,
Stan H.