SOLUTION: three times a first number decreased by a second number is one. the first number increased by twice the second number is 12. find the numbers
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Question 298681: three times a first number decreased by a second number is one. the first number increased by twice the second number is 12. find the numbers Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! three times a first number decreased by a second number is one. the first number increased by twice the second number is 12. find the numbers
let one number be x
& the other number be y
3x-y=1
x+2y=12 Multiply by 3 and subtract from above equation
3x-y -3(x+2y)=1 -3*12
3x-y-3x-6y=-35
-7y=-35
y=-35/-7
y=5
3x-y=1
3x-5=1
3x=6
x=6/2
x=2
x=2 y=5
