SOLUTION: The area of a square can be quadrupled by increasing the length by 12cm and the width by 2cm. What are the dimensions of the square? ( area of the square is {{{ x^2 }}} ) I'

Algebra ->  Expressions-with-variables -> SOLUTION: The area of a square can be quadrupled by increasing the length by 12cm and the width by 2cm. What are the dimensions of the square? ( area of the square is {{{ x^2 }}} ) I'      Log On


   



Question 298667: The area of a square can be quadrupled by increasing the length by 12cm and the width by 2cm.
What are the dimensions of the square?
( area of the square is +x%5E2+ )
I'm not sure if my start was correct but I started off with +%28l%2B12%29%28w%2B2%29=4x%5E2+, and then +4x%5E2+=+lw%2B2l%2B12w%2B24+ ..

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Remember that l=x and w=x
4x^2=x^2+2x+12x+24
3x^2=14x+24
(x-6)*(3x+4)=0