SOLUTION: Please help me solve this equation its an Algebra II Logarithm, {{{ 2^n=(3^(n-2))^(1/2) }}}

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Question 298644: Please help me solve this equation its an Algebra II Logarithm, +2%5En=%283%5E%28n-2%29%29%5E%281%2F2%29+
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
+2%5En=%283%5E%28n-2%29%29%5E%281%2F2%29+
2%5E2n+=+3%5E%28n-2%29
2n*log(2) = (n-2)*log(3)
2n*log(2) = n*log(3) - 2log(3)
2nlog(2) - nlog(3) = -log(9)
n*(log(3) - log(4)) = log(9)
n = log(9)/(log(3) - log(4))
n =~ -7.63768