SOLUTION: The length of a rectangle is 4in longer than its width.
If the perimeter of the rectangle is 48in , find its area.
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-> SOLUTION: The length of a rectangle is 4in longer than its width.
If the perimeter of the rectangle is 48in , find its area.
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Question 298521: The length of a rectangle is 4in longer than its width.
If the perimeter of the rectangle is 48in , find its area. Answer by blwinbbbles(106) (Show Source):
You can put this solution on YOUR website! so let l = length and w = width
we know the l = w + 4 and we know that 2l + 2w = 48
so use substitution:
2(w+4) + 2w = 48
2w + 8 + 2w = 48
4w + 8 = 48 subtract 8 from both sides
4w = 40 divide by 4
w = 10
now go back and sub 10 in for w
l = 10 + 4
l = 14
Now area is w x l
so 10 x 14 = area
10 x 14 = 140 square inches
Hope this helps
