SOLUTION: x+1+sqrt(x+4)=9 once I isolate the radical I end up with x+4=(8-X)(8-x) WHat do I do next.

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Question 298175: x+1+sqrt(x+4)=9
once I isolate the radical I end up with x+4=(8-X)(8-x) WHat do I do next.

Found 2 solutions by nerdybill, MathTherapy:
Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website!
x+4=(8-X)(8-x)
FOIL right side:
x+4= 64-8x-8x+x^2
x+4= 64-16x+x^2
x+4= x^2-16x+64
4= x^2-17x+64
0 = x^2-17x+60
0 = (x+8)(x-15)
.
x = {-8, 15}

Answer by MathTherapy(10858) (Show Source):
You can put this solution on YOUR website!
x+1+sqrt(x+4)=9
once I isolate the radical I end up with x+4=(8-X)(8-x) WHat do I do next.

x + 4 = (8 - x)(8 - x)------- Square both sides of equation

------ FOILing right-side of equation

------->

(x - 12)(x - 5) = 0

x = 12 or 5

However, when 12 is substituted back into the original equation, we get:

But, when 5 is substituted back into the original equation, we get:

Therefore, the only solution is