Question 29790: Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. Answer by ikdeep(226) (Show Source):
You can put this solution on YOUR website! Let the first odd integer = (2x+1)
Let the first odd integer = (2x+3)
According to the question ...
5 times the first integer is 12 more than 3 times the second.
so ....we get the equation
5(2x+1)= 3(2x+3) + 12.......
hope this will help you..
if you are unable to solve the equation, conatct me again.
Please feel free to revert back for any further queries