SOLUTION: log3 (x+3) + log3 (x-7) =2

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Question 29779: log3 (x+3) + log3 (x-7) =2
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
log(x+3) + log(x-7) =2
log[(x+3)(x-7)] = 2
(x+3)(x-7) = 3^2
x%5E2+-+4x+-+21+=+9
x%5E2+-+4x+-+30+=+0

This does not factorise, so use the quadratic formula. The answers are:

+2+%2B-+sqrt%2834%29+

jon.