SOLUTION: Solve: log(x+2) + log(x-1) =1
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Question 297725
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Solve: log(x+2) + log(x-1) =1
Answer by
user_dude2008(1862)
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log(x+2) + log(x-1) =1
log[(x+2)(x-1)] =1
(x+2)(x-1)=10
x^2+x-2=10
x^2+x-12=0
(x+4)(x-3)=0
x+4=0 or x-3=0
x=-4 or x=3
Only answer is x=3