SOLUTION: Solve: log(x+2) + log(x-1) =1

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Question 297725: Solve: log(x+2) + log(x-1) =1
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
log(x+2) + log(x-1) =1

log[(x+2)(x-1)] =1

(x+2)(x-1)=10

x^2+x-2=10

x^2+x-12=0

(x+4)(x-3)=0

x+4=0 or x-3=0

x=-4 or x=3

Only answer is x=3