SOLUTION: Two cars leave city A at the same time to travel to City B. One car travels at 72 km/h and the other at 78 km/h. If the slower car arrives 20 minutes after the faster car, how far
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Question 297367: Two cars leave city A at the same time to travel to City B. One car travels at 72 km/h and the other at 78 km/h. If the slower car arrives 20 minutes after the faster car, how far apart are City A and City B? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! D=RT
D=72(T+1/3)
D=78T
72(T+1/3=78T
72T+24=78T
72T-78T=-24
-6T=-24
T=-24/-6
T=4 HOURS.
D=78*4
D=312 MILES. ANS.
312=72(4+1/3)
312=288+24
312=312
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