SOLUTION: Find all the solutions if 0 degrees < or equal x < 360 2sin^2x - sinx = 1

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Question 297319: Find all the solutions if 0 degrees < or equal x < 360
2sin^2x - sinx = 1


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2sin^2x - sinx = 1
2sin^2(x) - sin(x) - 1 = 0
It's a quadratic in sin(x)
(2sin +1 )*(sin - 1) = 0
sin = -1/2
sin = 1
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sin = -1/2 --> x=210, 330
sin = 1 --> x = 90
All values of x in degrees