SOLUTION: one plane flies at a ground speed 50 miles per hour faster than another. on a particular flight, the faster plane requires 3 hours and the slower one 3 hours and 30 minutes. what i
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Question 297103: one plane flies at a ground speed 50 miles per hour faster than another. on a particular flight, the faster plane requires 3 hours and the slower one 3 hours and 30 minutes. what is the distance of the flight? Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! Speed of the slower plane = x miles per hour.
Speed of the faster plane = (x+50) miles per hour.
Rate * Time = Distance.
Faster plane equation becomes:
(x+50) * 3 = D
Slower plane equation becomes:
x * 3.5 = D
Since they both equal D, then they both equal each other and we get:
(x+50) * 3 = x * 3.5
Simplify to get:
3*x + 150 = 3.5*x
Subtract 3*x from both sides of the equation to get:
.5*x = 150
Divide both sides of the equation by .5 to get:
x = 300
The slower plane is flying at 300 miles per hour.
The faster plane is traveling at 350 miles per hour.
the equation for the faster plane becomes:
350 * 3 = D = 1050 miles.
The equation for the slower plane becomes:
300 * 3.5 = D = 1050 miles.
the distance is the same in both equations as it should be.
