SOLUTION: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height
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-> SOLUTION: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height
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Question 296981: The height in feet for a ball thrown upward at 48 feet per second is given by s(t)=-16t^(2)+48t, where t is the time in seconds after the ball is tossed. What is the maximum height that the ball will reach? Answer by richwmiller(17219) (Show Source):
