SOLUTION: {{{0<=(2x+3)/4<4}}} Can someone explain this please

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Question 296693: 0%3C=%282x%2B3%29%2F4%3C4
Can someone explain this please
Found 2 solutions by jim_thompson5910, richwmiller:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
0%3C=%282x%2B3%29%2F4%3C4 Start with the given compound in inequality.


0%2A4%3C=2x%2B3%3C4%2A4 Multiply all sides by 4.


0%3C=2x%2B3%3C16 Multiply.


0-3%3C=2x%3C16-3 Subtract 3 from all sides.


-3%3C=2x%3C13 Combine like terms.


-3%2F2%3C=x%3C13%2F2 Divide all sides by 2 to isolate 'x'.


So the solution is -3%2F2%3C=x%3C13%2F2 which in interval notation looks like [)

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
0<=(2x+3)/4<4
means that (2x+3)/4 is two things
greater than or equal to zero
and less than 4
multiply all three parts by 4
0<=2x+3<16
subtract 3
-3<=2x<13
-3/2<=x<13/2